std::find_end
Defined in header <algorithm> | ||
---|---|---|
(1) | ||
template< class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); | (until C++20) | |
template< class ForwardIt1, class ForwardIt2 > constexpr ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); | (since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); | (2) | (since C++17) |
(3) | ||
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); | (until C++20) | |
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > constexpr ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); | (since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); | (4) | (since C++17) |
Searches for the last occurrence of the sequence [
s_first
,
s_last
)
in the range [
first
,
last
)
.
operator==
.p
.policy
. These overloads do not participate in overload resolution unless
| (until C++20) |
| (since C++20) |
Parameters
first, last | - | the range of elements to examine |
s_first, s_last | - | the range of elements to search for |
policy | - | the execution policy to use. See execution policy for details. |
p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
While the signature does not need to have |
Type requirements | ||
-ForwardIt1 must meet the requirements of LegacyForwardIterator. |
||
-ForwardIt2 must meet the requirements of LegacyForwardIterator. |
Return value
Iterator to the beginning of last occurrence of the sequence [
s_first
,
s_last
)
in range [
first
,
last
)
.
If [
s_first
,
s_last
)
is empty or if no such sequence is found, last
is returned.
Complexity
Given \(\scriptsize N\)N as std::distance(first1, last1)
and \(\scriptsize S\)S as std::distance(first2, last2)
:
operator==
.p
.Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies,std::terminate
is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_alloc
is thrown.
Possible implementation
find_end (1) |
---|
template<class ForwardIt1, class ForwardIt2> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last) { if (s_first == s_last) return last; ForwardIt1 result = last; while (true) { ForwardIt1 new_result = std::search(first, last, s_first, s_last); if (new_result == last) break; else { result = new_result; first = result; ++first; } } return result; } |
find_end (3) |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p) { if (s_first == s_last) return last; ForwardIt1 result = last; while (true) { ForwardIt1 new_result = std::search(first, last, s_first, s_last, p); if (new_result == last) break; else { result = new_result; first = result; ++first; } } return result; } |
Example
#include <algorithm> #include <array> #include <cmath> #include <iostream> auto print_result = [](auto result, const auto& v) { result == v.end() ? std::cout << "Sequence not found\n" : std::cout << "Last occurrence is at: " << std::distance(v.begin(), result) << '\n'; }; int main() { const auto v = {1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4}; for (auto const& x : {std::array{1, 2, 3}, {4, 5, 6}}) { auto iter = std::find_end(v.begin(), v.end(), x.begin(), x.end()); // overload (1) print_result(iter, v); } for (auto const& x : {std::array{-1, -2, -3}, {-4, -5, -6}}) { auto iter = std::find_end(v.begin(), v.end(), x.begin(), x.end(), // overload (3) [](int x, int y) { return std::abs(x) == std::abs(y); }); print_result(iter, v); } }
Output:
Last occurrence is at: 8 Sequence not found Last occurrence is at: 8 Sequence not found
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 1205 | C++98 | the return value was unclear if [ s_first , s_last ) is empty | returns last in this case |
See also
searches for a range of elements (function template) |
|
returns true if one sequence is a subsequence of another (function template) |
|
finds the first two adjacent items that are equal (or satisfy a given predicate) (function template) |
|
(C++11) | finds the first element satisfying specific criteria (function template) |
searches for any one of a set of elements (function template) |
|
searches a range for a number of consecutive copies of an element (function template) |
|
(C++20) | finds the last sequence of elements in a certain range (niebloid) |
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