Knowing the futility of discounting in continuing problems, how can we say discounting has no role in control problems with function approximation?

Asked Apr 19 '22 at 17:51

Active Apr 23 '22 at 09:00

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Sutton-Barto (Section 10.4, page 254):

Based on the futility of discounting in continuing problems, how can we conclude that discounting has no role to play in control problems with function approximation?

edited Apr 23 '22 at 09:00

nbro

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asked Apr 19 '22 at 17:51

user3489173

Knowing the futility of discounting in continuing problems, how can we say discounting has no role in control problems with function approximation?

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