Renaming multiple files with Bash

Question

I have a lot of files to process and I need to replace their original names with this format in bash:

00000000000001_1.jpg 
00000000000002_1.jpg
00000000000003_1.jpg

and so on

dessert · Accepted Answer · 2018-03-19T23:20:15.997

4

Adapted from one of Oli's answers:

rename -n 's/.+/our $i; $i++; sprintf("%014d_1.jpg", $i)/e' *

This takes every file in the current directory and renames it with a number with 14 digits (I hope I counted correctly) followed by _1.jpg. our $i introduces a global variable i, which is then increased by one and printed with sprintf. e commands rename to evaluate the right side of the replacement (= everything between the second and the third /) as an expression rather than literally. If you're happy with the results, remove -n to perform the renaming.

If you want to dive into perl expressions and their beauty, the perldoc is the way to go.

edited Mar 19 '18 at 23:20

answered Mar 19 '18 at 23:13

dessert

39,982

This is a good approach. The Perl rename utility is powerful, flexible, and fast. Note that the approach you've shown here can be simplified (but it does work just fine, as written). – Eliah Kagan Mar 20 '18 at 05:43

Paul · Answer 2 · 2018-03-20T14:09:13.673

3

Would this works for you :

i=1
for file in *; do
    mv "$file" "$(printf %014d $i)_1.jpg"
    i=$((i+1))
done

It will rename every file in the current directory like this :

00000000000001_1.jpg
.
.
00000000000009_1.jpg
.
.
00000000000010_1.jpg
.
.

edited Mar 20 '18 at 14:09

answered Mar 19 '18 at 22:21

Paul

251

replace ._$file with _1.jpg and I think you've got it. – WinEunuuchs2Unix Mar 19 '18 at 23:10
I edited my answer, I thought _1.jpg was supposed to be the original file name. – Paul Mar 19 '18 at 23:57
Looking better. Just need to change ._1.jpg to _1.jpg then I think it's perfect. – WinEunuuchs2Unix Mar 20 '18 at 01:48

Renaming multiple files with Bash

2 Answers2