How to enumerate a variable in a loop starting at 01?

Question

I have a question

I have the rename command, but after I run the rename starting from 00, how to start from 01, please help me

this is the command that I use

for i in *.mkv; do
  new=$(printf "Movie - %02d.mkv" "$a")
  mv -i -- "$i" "$new"
  let a=a+1
done

Such kind of renaming could be easily done by using the command rename, here is a nice example: Renaming hundreds of files at once for proper sorting. — pa4080, Jul 15 '20 at 12:38

Ravexina · Accepted Answer · 2020-07-15T12:25:49.910

2

Simple as adding a variable (a=1) at the beginning:

#!/bin/bash
a=1
for i in *.mkv; do
  new=$(printf "Movie - %02d.mkv" "$a")
  mv -i -- "$i" "$new"
  let a=a+1
done

Here is in one line as you asked for:

a=1; for i in *.mkv; do new=$(printf "Movie - %02d.mkv" "$a"); mv -i -- "$i" "$new"; let a=a+1; done

edited Jul 15 '20 at 12:25

answered Jul 15 '20 at 11:40

Ravexina

score 1 · Answer 2 · answered Jul 15 '20 at 20:09

For exmaple,

#!/bin/bash
a=1
for i in *.mkv; do
  new=$(printf "Movie - %02d.mkv" "$a")
  mv -i -- "$i" "$new"
  ((a++))
done

On other hand, if you prefer a one-liner, rename command can do that:

rename 's/\d+/sprintf("Movie - %02d", $&)/e' *.mkv

2 Answers2