how to replace a word between double quotes?

Question

I need to replace a word between the quotes after equal sign using sed. but I'm unable to do it please suggest? #mfsbsd.rootpwhash="" look like #mfsbsd.rootpwhash="wsnk&*32jk"

cat loader | sed -e 's|["\'']||g' | sed 's/rootpwhash="[^"]*"/rootpwhash="abcd"/'

Did you find any answer useful? Providing feedback is useful for the community. — sancho.s ReinstateMonicaCellio, Mar 19 '21 at 20:05

score 0 · Answer 1 · answered Mar 09 '21 at 17:50

0

Maybe a matter of systematically escaping the " with the \ character? This works for me:

$ echo Name=\"\" | sed -e 's/\"\"/\"This should be filled in\"/'Name="This should be filled in"

To replace anything that is originally between the "":

$ echo Name=\"Original\" | sed -e 's/\".*\"/\"This should be filled in\"/'
Name="This should be filled in"

answered Mar 09 '21 at 17:50

vanadium

88,010

wow!nice. but i need user variable replaced word, im getting unmatched ''' error, echo mfsbsd.rootpwhash=" " | sed -e "s/".*"/$text/" – Sreekanth Chityala Mar 09 '21 at 18:01
That is not in your question. If, after having an answer on this question ("how to replace a word between double quotes?" is what you asked!) specific issues remain, then outline the specific issue in a new, specific question. It is not allowed here to change the nature of your question after the fact, so feel free to ask a different question. – vanadium Mar 10 '21 at 09:02

score 0 · Answer 2 · 2021-03-09T18:12:22.560

0

If your key-value pair is structured one per line, you only need to match the key-part. i.e., if you don't have to match the value too.

text=new; cat loader | \
sed "s/\(mfsbsd.rootpwhash\)=.*/\1=\"$text\"/"

edited Mar 09 '21 at 18:12

answered Mar 09 '21 at 18:01

good, mfsbsd.rootpwhash=sri its printing like this with cat loader | sed "s/(mfsbsd.rootpwhash)=.*/\1="$text"/" . how can i add double qoute to the string(sri) – Sreekanth Chityala Mar 09 '21 at 18:07
/\1=\"$text\"/" – Mar 09 '21 at 18:09
sorry to ask precise answer im new to scripting. i tried this not working cat loader | sed "s/(mfsbsd.rootpwhash)=.*/\1="$text"/ printing mfsbsd.rootpwhash=sri" before s not coming another double qoute. – Sreekanth Chityala Mar 09 '21 at 18:19
looks like you have missed the last quote – Mar 09 '21 at 18:20
sed: 1: "s/"."/"%6%GOrxqIbx.CmZ ...": bad flag in substitute command: 'l' im getting this error always. when im running this sed -i -e "s/(mfsbsd.rootpwhash)=./\1="$newpass"/" /bootpool/boot/loader.conf whenever i run this getting error bad flag in substitute command: 'l' with different letter which is not exists in my command. any sol – Sreekanth Chityala Mar 09 '21 at 20:09
if you are going to do an in-place substitution you need to place "loader" as an input file instead text=new; sed -i 's/$mfsbsd.rootpwhash$=.*/\1="'"$text"'"/' loader – Mar 09 '21 at 20:26
@Sreekanth Chityala use `` when commenting code ... – Mar 09 '21 at 20:32

score 0 · Answer 3 · answered Mar 09 '21 at 18:19

0

You can use double quotes, and escape special characters in your substitute variable

$ export TESTVAR="wsnk\&\*32jk"
$ cat loader | sed -e "s/\".*\"/\"$TESTVAR\"/"
#mfsbsd.rootpwhash="wsnk&*32jk"

answered Mar 09 '21 at 18:19

sancho.s ReinstateMonicaCellio

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how to replace a word between double quotes?

3 Answers3