alias with parameters

Question

I was recently starting to setup my usual alias. I ended up needing to pass more information than my alias originally needed

$ alias runserver = 'python manage.py runserver'
$ runserver 80  // turns out you need sudo
$ sudo runserver 80
$ sudo: runserver: command not found

Now as I was writing this i realized maybe the alias isn't set for root. Could that be it?

If not, could someone explain why this doesn't work.

Please and thank you

score 2 · Accepted Answer · edited Apr 13 '17 at 12:23

2

Note: the body of this question is a duplicate of Aliases not available when using sudo.

In the above question, they solved the sudo problem by aliasing sudo too:

alias sudo='sudo '

Note that the title is misleading, "alias with parameter" would be a function. Assuming that your runserver alias would accept a single argument, the port:

runserver(){ python manage.py runserver $1;}

If runserver accepts an unknown amount of parameters, pass all parameters using:

runserver(){ python manage.py runserver "$@";}

For the latter syntax, consult the bash manual.

edited Apr 13 '17 at 12:23

Community

1

answered Mar 12 '11 at 20:47

Lekensteyn

174,277

mm, yes, I always forget that hack. – geekosaur Mar 12 '11 at 20:48

score 0 · Answer 2 · answered Mar 12 '11 at 20:46

0

sudo doesn't see aliases in the invoking shell. Aliases in .bashrc will show up with sudo -s or sudo -i; the former is your .bashrc, the latter for root's.

In any case, wouldn't the easier way be alias runserver='sudo python manage.py runserver'?

answered Mar 12 '11 at 20:46

geekosaur

11,597

I dont always want to run it as root. – myusuf3 Mar 13 '11 at 00:21

alias with parameters

2 Answers2