How can I show date in YYYY-MM-DDTHH:MM:SS+ZZZZ format in LINUX? I need to write the creation date of a file say file1 in another file say file2 in given format. Help me to achieve this.
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The date format you are referring to is ISO 8601. Use the -I option to the date command to format dates according to this format (the s specifies precision up to integral seconds):
$ date -Is
2013-10-08T10:48:03+0300
To obtain the last modification time of a file (in seconds since the epoch), use the %Y format specifier with the stat command:
$ stat -c %Y file1
1378818806
Combining these two, use date -d to format the output of stat -c:
$ date -Is -d @`stat -c %Y file1`
2013-09-10T16:13:26+0300
So this is the statement that does what you need:
$ date -Is -d @`stat -c %Y file1` > file2
zwets
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You can display a date that way with this command:
$ date +%Y-%m-%dT%H:%M:%S%z
2013-10-08T07:38:45+0200
Many file systems do not store a file creation date so there is not always a method to get it. If the file has never been modified since its creation, this would work:
$ date -r file1 +%Y-%m-%dT%H:%M:%S%z > file2
$ cat file2
2013-10-08T07:32:52+0200
jlliagre
- 5,833
1
Does this help you?
ls -c -l file1 --time-style="+%Y-%m-%dT%H:%M:%S%z" > file 2
MadMike
- 4,244
- 8
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Combining my previous answer and that of @jlliagre, the most concise way to do what you want is:
date -Is -r file1 > file2
datemanual page,infodocumentation or--helpoutput mention the-Ioption. I finally found it here https://www.gnu.org/software/coreutils/manual/html_node/Options-for-date.html and of course in the source code too. – jlliagre Oct 09 '13 at 20:03man date(from coreutils 8.20 on Ubuntu 13.04) shows this option:-I[TIMESPEC],--iso-8601[=TIMESPEC] output date and time in ISO 8601 format. – zwets Oct 10 '13 at 05:36