How to script Subversion verification?

Question

Leading on from this question, I'm trying to write a bash script which will recurse two directories from the directory containing my subversion repositories, checking whether directories are repositories. There will be a mix of directories and repositories, and some repos hiding in those sub-dirs.

Any Subversion repos discovered should have their name printed to an output file, followed by the output of svnadmin verify.

I have the following snippet to check whether a directory is a repository:

svnlook info /path/to/repo >/dev/null

So I'm throwing away the svnlook output, a return code of 0 indicates that it is indeed a SVN repo. I could use this snippet, in an if statement to run svnadmin verify if 0 is returned.

I've tried:

find /dir/containing/repos -maxdepth 2 -type d -exec bash -c 'if [ "svnlook info {} >/dev/null" = 0 ] ;then ;echo "{}" >>output.txt ;svnadmin verify "{}" >>output.txt ;fi' \;

Though I get the following warning for each directory found:

bash: -c: -line 0: syntax error near unexpected token ';'

I think I'm trying to unnecessarily cram it all into one find command, which I'm getting wrong anyway. What would be the best way to structure this task?

Answer 1

You don't need ; after then in then ;echo "{}" >>output.txt.

Use :

then echo "{}" >>output.txt

Also note that rather than playing with {} use positional parameters of shell (i am not familiar with svn so relying upon your commands) :

find /dir/containing/repos -maxdepth 2 -type d -exec bash -c 'if svnlook info /path/to/repo >/dev/null ;then echo "$1" >>output.txt ;svnadmin verify "$1" >>output.txt ;fi' _ {} \;

• if svnlook info /path/to/repo >/dev/null will run the command and redirect the STDOUT to /dev/null

• If the svnlook info /path/to/repo command is successful (exit code 0), then echo "$1" >>output.txt ;svnadmin verify "$1" >>output.txt commands will be run

• Here we are using the directory names {} as the fist argument ($1) to be processed by shell.

• _ here is just a placeholder indicating positional parameter 0 as bash -c command starts considering any further argument after the command starting from 0. As _ is the zero-th argument, we can use {} as the first argument. Check man bash to get more idea.