Cannot open zip created with shell script

Question

I try to make a backup script, but when i create a zip with the script, and use cd myzip it sais that it dosnt exitst even when i can see it on the server with FileZilla.

This is my script:

TIME=BACKUPMC-`date +%d-%m-%Y-%H:%M`.zip
DEST="/home/daixhosting/d1"
zip -r $TIME /home/daixhosting/d1

Does someone know what the cause can be?

When i try to unzip it, it cant locate the file, i can only see it, but cannot do anything with it. — Casper Rasmussen, Aug 02 '15 at 15:32
Its as the script sais: BACKUPMC-02-08-2015-17:15.zip
That was the time i runned the script — Casper Rasmussen, Aug 02 '15 at 15:54
Whats the output of find / -type f -name 'BACKUPMC-02-08-2015-17:15.zip' ? — heemayl, Aug 02 '15 at 18:42
That means there is no such file..are you sure about the file names ? — heemayl, Aug 02 '15 at 18:48
@heemayl Even if i try to open/download the file with FileZilla it sais that theres no file with that name, as you can see here: link — Casper Rasmussen, Aug 02 '15 at 18:58
go to /root and check if the file exists or not..if not then filezilla is somehow making a mistake. — heemayl, Aug 02 '15 at 19:03
Also run for i in /root/*; do printf '%s\n' "$i" | od -c; done — heemayl, Aug 02 '15 at 19:24
@heemayl when i run the file command it gives me this: http://pastebin.com/kjMyeC2A — Casper Rasmussen, Aug 02 '15 at 20:10
That means the file does not exist..can you add a screenshot of ls -al /root — heemayl, Aug 02 '15 at 21:30
@heemayl This is wired. Now the file is gone... it was there in the beginning... Should i run the script again? — Casper Rasmussen, Aug 02 '15 at 21:37
Damn... this is the worst... i was looking on the wrong server.. The file is still there. This is the output from the right server: http://pastebin.com/8UES9Yt0
And the file command gives me this: http://pastebin.com/uXu2AZux — Casper Rasmussen, Aug 02 '15 at 21:45
You have files with carriage return in them..thats the reason you were not finding them.. run this command and then check in the normal manner.. at first go to the directory containing files using cd and then run for file in *; do mv -i "$file" "$(sed 's/\r//g'<<<"$file")"; done — heemayl, Aug 02 '15 at 21:54
@heemayl It gives me this when i try running the command: http://pastebin.com/7f5dYMXq — Casper Rasmussen, Aug 02 '15 at 21:59
@heemayl i might think i should run it like this: http://pastebin.com/M4pzpDnw
And that gave me no output, and it still not working. Am i running it right? — Casper Rasmussen, Aug 02 '15 at 22:07
At first go to the directory, then run bash, then run for file in *; do mv -i "$file" "$(sed 's/\r//g'<<<"$file")"; done — heemayl, Aug 02 '15 at 22:09
I have added an answer..please select that as accepted by clicking the tick mark on the left of the answer so that this issue can be marked as solved.. — heemayl, Aug 02 '15 at 22:17

score 1 · Answer 1 · answered Aug 02 '15 at 22:15

You have carriage return \r in the file names, as a result you are not being able to parse the files using usual manner.

To remove all the \r characters from the file names run the following command in bash from the directory containing the files :

for file in *; do mv -i "$file" "$(sed 's/\r//g'<<<"$file")"; done

Now all the files should not have \r in them , now you can zip them using usual manner e.g. :

zip -r foo.zip /home/foobar/spam/

score 0 · Answer 2 · answered Aug 02 '15 at 16:28

0

Try changing the name of the zip file to a file name without the ":".

If that's not the problem, consider that the file could be corrupted. So, you'll try to repair it and maybe save a part of the information. Some way for that is, for example,

zip -F broke.zip --out pleasework.zip

or

zip -FF broke.zip --out pleasework.zip

answered Aug 02 '15 at 16:28

pierre_q_pound

1

i tried that at the sais that it can't find the zip fil. – Casper Rasmussen Aug 02 '15 at 18:36

Cannot open zip created with shell script

2 Answers2