awk: search for pattern stored in an array

Question

I use awk to parse a file. Have stored pattern words in an awk array. Would like to do something like this.

if ( $0 ~ / arr[1] / ){
blah
}

I want to check if the pattern stored in the array element is found in the current line which is being parsed.

I want to check if the pattern stored in the array element is found in the current line. — Andromeda64, Nov 18 '16 at 20:55

score 1 · Answer 1 · answered Nov 18 '16 at 21:03

1

Just use the array accessing afterwards, no need for the // as then the arr[1] will be taken as a Regex pattern, do:

if ( $0 ~ arr[1] ){ blah }

Example:

% awk 'BEGIN{a[1]="foo"} {if ($0 ~ /a[1]/) print "Matched"}' <<<'foobar'  
% awk 'BEGIN{a[1]="foo"} {if ($0 ~ a[1]) print "Matched"}' <<<'foobar' 
Matched

answered Nov 18 '16 at 21:03

heemayl

91,753

@andromeda64 No problem. Don't forget to mark the answer as accepted. – heemayl Nov 18 '16 at 21:06
I did, but since I am new, it has recorded the feedback but would not show to public. – Andromeda64 Nov 18 '16 at 21:07

awk: search for pattern stored in an array

1 Answers1