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I have written a code in python language that usage subprocess.call() method and print method, i am using this code as nautilus script and it is working fine. but there is no way to know that script is working right now, i can see the effect only after script completed.

I want this script to run in terminal so that i can know that script is running and there is a print method in the code that need to be print text when script fail but it does not shows up.

If there is other method than terminal please tell me.

Nishant Bhakta
  • 173
  • Well, you could raise a terminal window from script and print stuff there. You could also display a small popup with zenity that shows the script is working. One can also write a "progress" popup, either with zenity or in Python via Gtk API, but that's overly complex for a nautilus script I'd say. – Sergiy Kolodyazhnyy Jul 28 '17 at 18:13
  • Sometimes script output to the terminal ends up in /var/log/syslog when run in GUI. However @SergiyKolodyazhnyy hasn't pointed out to me before this isn't always the case. – WinEunuuchs2Unix Jul 28 '17 at 18:23
  • This is probably totally overdoing things, but https://askubuntu.com/a/757599/72216. Used it to notice if and when my rsync backup was running :). Just to mention. – Jacob Vlijm Jul 28 '17 at 18:42

1 Answers1

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Here is small snippet in bash, you can easy rewrite in python, it notify user trying to find a possible way:

#!/usr/bin/env bash

have_command() {
  type -p "$1" >/dev/null
}

try() {
  have_command "$1" && "$@"
}

in_terminal() {
  [ -t 0 ]
}

notify_user() {
  local msg="${2:-Error}: $1"
  echo "$msg" >&2
  in_terminal && return
  try notify-send "$msg" && return
  try yad --info --text="$msg" && return
  try zenity --info --text="$msg" && return
  try xmessage -buttons Ok:0 -nearmouse "$msg" -timeout 10 && return
  return
}

Install notify-send and you'll get nice messages

LeonidMew
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