Start Specific Terminal on Startup

Question

I coded an application using libpcap and ncurses. Obviously, this application is supposed to run in the terminal.

Therefore, I created a script that launches my application in gnome-terminal with a fixed size:

#!/bin/sh
gnome-terminal --geometry=75x36+0+0 --command="myapplication"'

I want to execute that on startup (after the desktop of the current logged in user has shown up). It is important to run this as root. Otherwise, libpcap won't be able to sniff for packets. I am aware of all the risks involved.

I created the following .service file:

[Unit]
Description=My Application

[Service]
User=root
Type=simple
ExecStart=/usr/local/bin/myshellfile

[Install]
WantedBy=multi-user.target

And I put it in /etc/systemd/system/myservice.service and preset it with

sudo systemctl preset myservice.service

Nevertheless, it does not work. What am I doing wrong here? Running Ubuntu 16.04 in an updated state.

Should the terminal remain open? You may use Startup applications. I have an idea how that could be done. — pa4080, Oct 17 '17 at 11:02
@pa4080 Exactly! My application has a CLI, so it needs to stay open. Its blocking btw - so as soon as you run the application, it stays open and doesn't close itself :) — TacoVox, Oct 17 '17 at 12:39
Hi, TacoVox, sorry for the late answer, but I had not enough free time previous days. — pa4080, Oct 24 '17 at 12:47

pa4080 · Accepted Answer · 2017-10-25T14:14:26.250

There are few possible methods to launch GUI application (as gmome-terminal) at system startup and maybe the most appropriate is to use Startup Applications (see also). In this way the app will be started when the user login. (In every other method we should export some desktop envvars to be able to do that.)

To be able to test my answer, I created executable file, called myapp, located in /usr/local/bin. It adds just the current date and time within a file in the /root directory, so we will need root (sudo) permissions to run the script:

#!/bin/bash
date >> /root/date.txt

We can grant permissions to a specific user to run a command without password via sudo. No matter whether the user belongs to the sudoers group or not. We can use sudo visudo to edit safely /etc/sudoers and add one or more lines as these:

user1 ALL=(ALL) NOPASSWD: /usr/local/bin/myapp
user2 ALL=(ALL) NOPASSWD: /usr/local/bin/myapp

The better idea is to create a separate file, for example /etc/sudoers.d/myapp, where to put these rules. For this purpose we shall use the command: sudo visudo -f /etc/sudoers.d/myapp.

Now user1 and user2 should be able to run sudo myapp without password.

Note: Always use the command visudo to edit the sudoers file to make sure you do not lock yourself out of the system – just in case you accidentally write something incorrect to the sudoers file. visudo will save your modified file to a temporary location and will only overwrite the real sudoers file if the modified file can be parsed without errors... source.

The next step is to modify the startup script. Let's call it myapp_startup and place it into the same directory /usr/local/bin. The script content should be:

#!/bin/sh
gnome-terminal --geometry=75x36+0+0 -x bash -c "sudo myapp; exec bash"

Detailed explanation about the above command is provided here.
If you want to minimise the window automatically use: this approach.

Now we can create an entry in Startup Applications as this:

Additionally we can modify the startup script in this way: sleep 3 && gnome-terminal ... to launch the new terminal window after the entire desktop is initialised.
When the script isn't located within a directory that is added to user's $PATH variable (echo $PATH) we should use the full path, for example: /usr/local/bin/myapp_startup.

Start Specific Terminal on Startup

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