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4pie0

481

reputation

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Basingstoke, UK
Member since January 17 2013
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Last seen Feb 25 '22 at 20:19

>> p = [1 0 1];

>> roots(p)

ans =

0.000000000000000 + 1.000000000000000i

0.000000000000000 - 1.000000000000000i